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Lyla

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Everything posted by Lyla

  1. Emily Didonato [10] Adriana Lima [10] Monica Jagaciak [9] Irina Shayk [4] Sara Sampaio [6] Shanina Shaik [7] Barbara Palvin [5] Miranda Kerr [3] Isabeli Fontana [6] Andreea Diaconu [6]
  2. Lyla replied to PinkCouture's topic in Television
    Oh thanks God that it's not T. Swift! I read about Rachel McAdams too! That would be a fair choice! I kind of like her as well. And now you made me curious about Lone Survivor, though I've always been that about Taylor. He must be a good actor if a big studio like Disney had trust in him to give him the main role in their movie. But I believe you that those action movies are crap. But Taylor is... :wub2:
  3. Lyla replied to PinkCouture's topic in Television
    I saw him only in FNL but I loved him as Tim Riggins!
  4. Lyla replied to PinkCouture's topic in Television
    Taylor Kitsch
  5. CHANEL COLLECTION RÊVERIE PARISIENNE spring 2015 make up collection
  6. Also, Heidi got it 3 times. At this point, VS has made it well known that Adriana is the Top Model of VS and I think that somehow they will want Adriana to surpass that record. Heidi has been everywhere and doesn't really scream "pure VS" whenever someone mentions her name as opposed to Adriana. Hell, that's a haters biggest remark "Adriana only does vs blah blah blah" I've noticed the past few years it seems that they want us to ween out Tyra and Gisele and Heidi as the face of VS and give it to Adriana. I think it would be only fitting to give Adriana a third. 14 years people ffs lol. 3 in 14 years when you've been the top Angel for 8 years(and one could argue the top 3 angels 10, on top of opebing a show while the likes of Tyra, Gisele, Heidi and Karolina are in the same show) isn't much of a shocker really. I promise this will be the end of me fangirling for the week gahaha. imo Karlie is the Top Model of VS at the moment. She's everywhere. Though was everywhere last year too... edit: oops, I misunderstood a bit your sentence. So...maybe VS thinks that Adriana is their TOPmodel, but Karlie is atm. But I know nothing...
  7. Emily Didonato [10] Adriana Lima [10] Monica Jagaciak [10] Irina Shayk [6] Sara Sampaio [8] Shanina Shaik [8] Barbara Palvin [8] Miranda Kerr [6] Isabeli Fontana [8] Andreea Diaconu [9]
  8. My present for my 25th wasn't this fabulous unfortunately... so now I'm thinking what did I wrong?! lol
  9. Emily Didonato [10] Adriana Lima [10] Monica Jagaciak [10] Irina Shayk [8] Sara Sampaio [10] Shanina Shaik [9] Barbara Palvin [9] Miranda Kerr [8] Isabeli Fontana [9] Andreea Diaconu [10]
  10. Niiice! My favs! Emily Didonato [10] Adriana Lima [10] Monica Jagaciak [10] Irina Shayk [9] Sara Sampaio [10] Shanina Shaik [10] Barbara Palvin [10] Miranda Kerr [10] Isabeli Fontana [10] Andreea Diaconu [10]
  11. Someone make a list please!
  12. Tyra Banks [0] Karolina Kurkova [1] Gisele!
  13. Tyra Banks [1] Rosie Huntington Whiteley [0] OUT Karolina Kurkova [2]
  14. Gisele Bundchen [1] Tyra Banks [1] Rosie Huntington Whiteley [1] Karolina Kurkova [2]
  15. Gisele Bundchen [3] Tyra Banks [1] Rosie Huntington Whiteley [2] Karolina Kurkova [2]
  16. Gisele Bundchen [9] Tyra Banks [1] Izabel Goulart [5] Marisa Miller [2] Rosie Huntington Whiteley [6] Karolina Kurkova [6]
  17. Gisele Bundchen [10] Tyra Banks [2] Izabel Goulart [6] Marisa Miller [4] Rosie Huntington Whiteley [7] Karolina Kurkova [7]
  18. Gisele Bundchen [10] Tyra Banks [2] Izabel Goulart [7] Marisa Miller [6] Erin Heatherton [1] Rosie Huntington Whiteley [7] Karolina Kurkova [8]
  19. Totally! I love Ed! I want him to wear the FB! :wub2:
  20. Gisele Bundchen [10] Tyra Banks [2] Izabel Goulart [8] Marisa Miller [6] Erin Heatherton [2] Rosie Huntington Whiteley [7] Karolina Kurkova [8]
  21. Gisele Bundchen [10] Tyra Banks [3] Izabel Goulart [8]Marisa Miller [6]Erin Heatherton [3]Rosie Huntington Whiteley [8]Karolina Kurkova [9]
  22. Lyla replied to a post in a topic in Music
  23. Gisele Bundchen [10] Tyra Banks [3] Izabel Goulart [9] Marisa Miller [6] Erin Heatherton [3] Rosie Huntington Whiteley [9] Karolina Kurkova [9]